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Advanced · Level 12

Continuity & differentiability

Standard derivatives, the chain and product rules, and continuity.

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The idea

To find how fast a combined function changes, use simple rules for each piece.

xy−3−2−1123−11234|x|corner
xy−3−2−1123−11234|x|corner

Look: y = |x| has no break, but the sharp corner at 0 has no single steepness.

✏️ Your turn!

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  1. 1d/dx (sin 3x)

  2. 2d/dx (x²)

  3. 3d/dx (x eˣ)

! Careful!

  • ✗Forgetting to multiply by the inside’s derivative.

    ✓Chain rule: × 6x.

  • ✗(uv)′ = u′ × v′.

    ✓Product rule: u′v + uv′.

See the whole lesson on one page

To find how fast a combined function changes, use simple rules for each piece.

Chain rule: derivative of the outside × derivative of the inside. A graph with no breaks is continuous; a sharp corner has no single steepness.

Think of it like thisA function inside a function is like nesting dolls. The chain rule: open the outside doll, then the inside one, and multiply.

xy−3−2−1123−11234|x|corner
xy−3−2−1123−11234|x|corner
y = |x| has no break, but the sharp corner at 0 has no single steepness.

Solved together

Question

Find the derivative of (3x² + 1)⁵.

  1. Outside: ( )⁵. Its derivative: 5( )⁴.

    5(3x² + 1)⁴
  2. Inside: 3x² + 1. Its derivative: 6x.

    6x
  3. Multiply them.

    5(3x² + 1)⁴ × 6x = 30x(3x² + 1)⁴

Answer30x(3x² + 1)⁴.

For older learners and grown-ups: a little more

Quotient rule: (u/v)′ = (u′v − uv′)/v². Example: d/dx [x/(x + 1)] = 1/(x + 1)².

Now practise it

Kanakku makes new questions on continuity & differentiability every time. It shows the working and gives a hint when you are stuck.

Play and practise