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VerLearn Tamil through proverbs, poetry and play.
Advanced · Level 11

Permutations & combinations

Counting arrangements and selections.

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The idea

To count choices, multiply the number of options at each step.

5place 1×4place 2×3place 35 × 4 × 3 = 60 ways

Look: Gold, silver and bronze from 5 runners: 5 choices, then 4, then 3.

✏️ Your turn!

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  1. 14! = ?

  2. 25 people in a row: how many orders?

  3. 3Handshakes among 10 people?

! Careful!

  • ✗Using arrangements for a team.

    ✓Teams have no order: divide by the repeats.

  • ✗0! = 0.

    ✓0! = 1.

See the whole lesson on one page

To count choices, multiply the number of options at each step.

Arrangements (order matters): 1st, 2nd, 3rd place. Selections (order does not matter): picking a team. A selection counts each group once.

Think of it like this3 shirts and 2 pants make 3 × 2 = 6 different outfits.

n!
n × (n − 1) × … × 1. So 4! = 24.
5place 1×4place 2×3place 35 × 4 × 3 = 60 ways
Gold, silver and bronze from 5 runners: 5 choices, then 4, then 3.

Solved together

Question

From 5 runners, how many ways can gold, silver and bronze be given? How many different teams of 3?

  1. Medals: order matters. Fill each place.

    5 × 4 × 3 = 60
  2. A team: order does not matter. Each team was counted 3 × 2 × 1 = 6 times in those 60.

    60 ÷ 6 = 10

AnswerMedals: 60 ways. Teams: 10.

For older learners and grown-ups: a little more

ⁿPᵣ = n!/(n − r)! counts arrangements; ⁿCᵣ = n!/[r!(n − r)!] counts selections. Repeated letters: BANANA has 6!/(3! × 2!) = 60 arrangements.

Now practise it

Kanakku makes new questions on permutations & combinations every time. It shows the working and gives a hint when you are stuck.

Play and practise